![apex sql insert action apex sql insert action](https://dz2cdn1.dzone.com/storage/temp/11421655-apex-item-1.png)
- #Apex sql insert action how to#
- #Apex sql insert action install#
- #Apex sql insert action update#
- #Apex sql insert action code#
What does this have to do with your APEX application? In all my applications I tend to set the default date format to DD-MON-YYYY as it’s very explicit. This makes sense that one would expect to really be 0. world leading Oracle experts) and they all got it wrong as well (myself included).īy using a date format of DD-MON-YYYY if a user does not explicitly enter a four digit year, Oracle will left pad the number with 0s. I reached out to several Oracle ACEs (i.e. If you thought an error would be raised you’re in good company. The correct answer is that the query returns: 2. I recently asked this same question on Twitter and the results were quite interesting given that this should be a very straight forward answer. Without checking, what do you think happens/returns running the following query: 1
![apex sql insert action apex sql insert action](https://www.traust.com/wp-content/uploads/2020/10/3.-APEX-LOV-Function-Body-Return.png)
There’s been some feedback I’ve received on this so read all the way through
#Apex sql insert action update#
If you think there’s some additional elements that I should add to this list please update the Gist Share Comments Once I found the problem item I could easily resolve why it was changing and the warning didn’t show up any more. Could explicitly loop through all APEX page items using the undocumented function that Neil Fernandez wrote about.Consider using em().isChanged() syntax.I’ve included a direct reference got Github Gist so that if updated it’ll be reflected here Here is the script I created to find out which item(s) changed which is based on this article: Instead I created a script to find out which page item had changed. I tried a few quick checks to see if I could isolate which page item was causing the issue but wasn’t able to easily find it. If you’re not too familiar with how this message works / is configured read APEX: Warn on Unsaved Changes when navigating away from the page despite not having explicitly changed any values. When testing the page I kept getting the This page is asking you to confirm that you want to leave - data you have entered may not be saved. This is not usually a recommended approach (given that it can add complexity) but was justified given the business requirements. I was recently developing an APEX page that had a lot of page items and a lot of Dynamic Actions (DA) on it. In our case it would be recommended to have a returning into clause to get back the invoice_batch_id to be used elsewhere. To get around this you need to use the keyword default instead of null: 1 SQL Error: ORA-32795: cannot insert into a generated always identity columnģ2795.0000 - "cannot insert into a generated always identity column" Insert into invoice_batch(invoice_batch_id) But what do you put in there? If null is used the following happens: 1
#Apex sql insert action code#
The above code raises an error as Oracle requires a values clause. SQL Error: ORA-00926: missing VALUES keyword Suppose you want to insert a record into the invoice_batch table just to get an invoice_batch_id it could look like: 1 Invoice_batch_id number generated always as identity not null
#Apex sql insert action how to#
So how do you insert a record into a table with no values? The follow examples shows how to do this in Oracle:
![apex sql insert action apex sql insert action](https://www.teachucomp.com/wp-content/uploads/blog-11-29-2021-actionbuttonsinpowerpoint-460x260_c.jpg)
Before creating an invoice, the parent record ( invoice_batch) needs to be created. All the invoices that are generated at the same time should be part of the same invoice_batch. An example of why you’d want to do such a thing is if you need to generate invoices.
![apex sql insert action apex sql insert action](https://i.stack.imgur.com/jCWdU.png)
Suppose you needed to create a record in a table just to generate an id field which is automatically generated (as an identity column). That said there’s a warning message for a reason and I and hope there’s a Java 11 update soon that resolves the issue. I’ve only tried this for a day now and everything seems to be stable. When you start SQL Deeveloper a new warning message will appear that states You are attempting to run with Java 17.0.1. # Can manually open file and edit or just run below and it'll add it to the bottom of the fileĮcho "SetJavaHome /Library/Java/JavaVirtualMachines/jdk-17.0.1.jdk/Contents/Home" > nf # Find the most recent one (mine is 21.2.1) and open that directory # Can verify that it's in your JavaHome by running: (optional)ĭefine SetJavaHome in SQL Developer configuration 1 usr/libexec/java_home -v17 /Library/Java/JavaVirtualMachines/jdk-17.0.1.jdk/Contents/Home Sudo mv openjdk-17.0.1_macos-圆4_ /Library/Java/JavaVirtualMachines/ I got the following instructions from this blog post.
#Apex sql insert action install#
With the help of a few people on Twitter and Vito Campanelli I was able to get it working by doing the following steps: Upgrade / Install Java 17 After some research I found that it’s a Java 11 issue with the latest version of macOS. If you’ve upgraded to macOS Monterey and try to use Oracle SQL Developer you may experience an issue that it starts and then closes after a few minutes.